Solveeit Logo
Login

Question

Question: The rate law for reaction \(A + 2B = C + 2D\) will be....

The rate law for reaction A+2B=C+2DA + 2B = C + 2D will be.

A

Rate =K[A][B]= K\lbrack A\rbrack\lbrack B\rbrack

B

Rate =K[A][2B]= K\lbrack A\rbrack\lbrack 2B\rbrack

C

Rate =K[A][B]2= K\lbrack A\rbrack\lbrack B\rbrack^{2}

D

Rate =K[C][D]2[A][B]2= K\frac{\lbrack C\rbrack\lbrack D\rbrack^{2}}{\lbrack A\rbrack\lbrack B\rbrack^{2}}

Answer

Rate =K[A][B]2= K\lbrack A\rbrack\lbrack B\rbrack^{2}

Explanation

Solution

The rate law for an reaction can be given by; rate =K(A)(B)2K(A)(B)^{2}, i.e. the powers are raised which are given as coefficient of reactant.