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Chemistry Question on Chemical Kinetics

The rate constant of reaction is 0.69×10−2min−10.69 \times 10^{-2} min ^{-1} and the initial concentration is 0.2 molL−10.2\, mol L ^{-1}. The half-life period is

A

800 sec

B

600 sec

C

400 sec

D

6024 sec

Answer

600 sec

Explanation

Solution

Rate constant = 0.69×10−2min⁡−10.69 \times 10^{-2} \min^{-1} This unit (i.e. $min^{-1})ischaracteristicsoffirstorderreaction.Forfirstorderreaction,halflifetimeisgivenas:) is characteristics of first order reaction. For first order reaction, half life time is given as : t_{1 / 2}=\frac{0.693}{k_{1}}=\frac{0.693}{0.69 \times 10^{-2}}=1.004 \times 10^{2} \min t_{1 / 2}=100.4,\min =6024$