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Question: The rate constant of a first order reaction is \(3 \times 10^{- 6}\) per second. If the initial conc...

The rate constant of a first order reaction is 3×10−63 \times 10^{- 6} per second. If the initial concentration is 0.10mol, the initial rate of reaction is

A

3×10−5mol 6mus−13 \times 10^{- 5}mol\mspace{6mu} s^{- 1}

B

3×10−6mol 6mus−13 \times 10^{- 6}mol\mspace{6mu} s^{- 1}

C

3×10−8mol 6mus−13 \times 10^{- 8}mol\mspace{6mu} s^{- 1}

D

3×10−7mol 6mus−13 \times 10^{- 7}mol\mspace{6mu} s^{- 1}

Answer

3×10−7mol 6mus−13 \times 10^{- 7}mol\mspace{6mu} s^{- 1}

Explanation

Solution

Given that, rate constant for first order reaction (k)

= 3×10−63 \times 10^{- 6} per sec and initial concentration (1) = 0.10 mol we know that initial rate of reaction

= k(a)=3×10−6×0.10=3×10−7mol 6musec⁡−1k(a) = 3 \times 10^{- 6} \times 0.10 = 3 \times 10^{- 7}mol\mspace{6mu}\sec^{- 1}{}