Question

The rate constant K1 of a reaction is found to be doubles that of rate constant K2 of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature (E1 and E2) canbe represented as :

• A. E1> E2
• B. E1< E2
• C. E1 = E2
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$K_{1} = A_{1}e^{- E_{1}/RT}andK_{2} = A_{2}e^{- E_{2}/RT}$

$\frac{K_{1}}{K_{2}} = \frac{A_{1}}{A_{2}} = e^{\left( E_{2} - E_{1} \right)/RT};A_{1}andA_{2}arenotgiven.$