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Question

Question: The rate constant (k') of one reaction is double of the rate constant (k") of another reaction. Then...

The rate constant (k') of one reaction is double of the rate constant (k") of another reaction. Then the relationship between the corresponding activation energies of the two reactions (Ea' and Ea") will be -

A

Ea' >Ea"

B

Ea' = Ea"

C

Ea' <Ea"

D

Ea' = 4Ea"

Answer

Ea' <Ea"

Explanation

Solution

As k' > k'', Ea' < Ea"

\because Greater the rate constant, less is the activation energy.