Question

The rate constant for the reaction, 2N₂O₅® 4NO₂ + O₂ is 3 × 10^–5 s^–1. If the rate of reaction is 2.4 × 10^–5mol L^–1 s^–1 , then concentration of N₂O₅ is-

• A. 1.4 (M)
• B. 1.2 (M)
• C. 0.04 (M)
• D. 0.8 (M)

Answer 1

Answer: (D)

0.8 (M)

Answer 2

Order of reaction is Ist \ [N₂O₅] =

= $\frac{2.4 \times 10^{- 5}}{3 \times 10^{- 5}}$= 0.8 (M)