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Chemistry Question on Chemical Kinetics

The rate constant for forward reaction and backward reaction of hydrolysis of ester are 1.1×10−21.1 \times 10^{-2} and 1.5×10−31.5 \times 10^{-3} per minute respectively. Equilibrium constant for the reaction is CH3COOC2H5+H2O⇌CH3COOH+C2H5OHCH _{3} COOC _{2} H _{5}+ H _{2} O \rightleftharpoons CH _{3} COOH + C _{2} H _{5} OH

A

33.7

B

7.33

C

5.33

D

33.3

Answer

7.33

Explanation

Solution

kf=1.1×10−2,kb=1.5×10−3k_{f}=1.1 \times 10^{-2}, k_{b}=1.5 \times 10^{-3} Kc=kfkb=1.1×10−21.5×10−3=7.33K_{c}=\frac{k_{f}}{k_{b}}=\frac{1.1 \times 10^{-2}}{1.5 \times 10^{-3}}=7.33