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Question

Chemistry Question on Chemical Kinetics

The rate constant for a first order reaction is 4.606×103s14.606 \times 10^{-3} s^{-1}. The time required to reduce 2.0g2.0\,g of the reactant to 0.2g0.2\,g is :

A

100 s

B

200 s

C

500 s

D

1000 s

Answer

500 s

Explanation

Solution

K=2.303tlogaaxK=\frac{2.303}{t}log\, \frac{a}{a-x} t=2.3034.606×103t=\frac{2.303}{4.606\times 10^{-3}} log20.2log\,\frac{2}{0.2} =10002log10=\frac{1000}{2} \,log\,10 =500sec=500\,sec (as log 10=1)10=1)