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Question

Question: The range R of projectile is same when its maximum heights are h<sub>1</sub> and h<sub>2</sub>. What...

The range R of projectile is same when its maximum heights are h1 and h2. What is the relation between R and h1 and h2

A

R=h1h2R = \sqrt{h_{1}h_{2}}

B

R=2h1h2R = \sqrt{2h_{1}h_{2}}

C

R=2h1h2R = 2\sqrt{h_{1}h_{2}}

D

R=4h1h2R = 4\sqrt{h_{1}h_{2}}

Answer

R=4h1h2R = 4\sqrt{h_{1}h_{2}}

Explanation

Solution

For equal ranges body should be projected with angle θ\thetaor (90oθ)(90^{o} - \theta) from the horizontal.

And for these angles : h1=u2sin2θ2gh_{1} = \frac{u^{2}\sin^{2}\theta}{2g} and h2=u2cos2θ2gh_{2} = \frac{u^{2}\cos^{2}\theta}{2g}

by multiplication of both height : h1h2=u2sin2θcos2θ4g2=116(u2sin2θg)2h_{1}h_{2} = \frac{u^{2}\sin^{2} ⥂ \theta\cos^{2} ⥂ \theta}{4g^{2}} = \frac{1}{16}\left( \frac{u^{2}\sin 2\theta}{g} \right)^{2}

16h1h2=R216h_{1}h_{2} = R^{2}R=4h1h2R = 4\sqrt{h_{1}h_{2}}