Question
Mathematics Question on Functions
The range of the function f(x)x2+x+1x2−x+1 where x∈R, is
A
(−∞,3]
B
(−∞,∞)
C
[3,∞)
D
[31,3]
Answer
[31,3]
Explanation
Solution
Let y=x2+x+1x2−x+1 ⇒ x2(y−1)+4(y+1)+(y−1)=0 Now, D≥0 ⇒ (y+1)2−4(y−1)2≥0 ⇒ −3y2−3+10y≥0 ⇒ 3y2−10y+3≤0 ⇒ y=610±64≤0 (y−31)(y−3)≤0 ⇒ y∈[31,3]