The range of the function f(x) = 2sin(3x) +1 is equal to | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The range of the function f(x) = 2sin(3x) +1 is equal to

A

[-1, 1]

B

$[\frac{-1}{3},\frac{1}{3}]$

C

[-2, 1]

D

[-1, 2]

E

[-1, 3]

Answer

[-1, 3]

Explanation

Solution

The correct option is (E) : [-1, 3]