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Question

Question: The range of random variable X is 0, 1, 2,... ∞ and P(x=k) = \(\frac { c ( k + 1 ) } { 2 ^ { k } }...

The range of random variable X is 0, 1, 2,... ∞ and P(x=k)

= c(k+1)2k\frac { c ( k + 1 ) } { 2 ^ { k } } ,for k=0,1,2,... then C=

A

¼

B

1/3

C

½

D

1/5

Answer

¼

Explanation

Solution

k=0P(x=k)=1\sum _ { \mathrm { k } = 0 } ^ { \infty } \mathrm { P } ( \mathrm { x } = \mathrm { k } ) = 1 ;

c = 1

C; c(2+2) = 1; c = ¼