The range of f(x) = (4\sin^{-1}(\frac{x^2}{x^2+1})) is | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

The range of f(x) = $4\sin^{-1}(\frac{x^2}{x^2+1})$ is

A

$[0,\pi]$

B

$[0,\pi)$

C

$[0,2\pi]$

D

$[0,2\pi)$

Answer

$[0,2\pi)$

Explanation

Solution

The correct answer is (D) : $[0,2\pi)$