Question

The range of a projectile when launched at an angle 15º with the horizontal is 1.5 km. What will be the range of that projectile when launched with the same velocity at an angle 45º to the horizontal?

• A. 0.75 km
• B. 1.5 km
• C. 3.0 km
• D. 6.0 km

Answer 1

Answer: (C)

3.0 km

Answer 2

At q = 15⁰,

R =$\frac{u^{2}\sin 30º}{g}$= 1.5 km

̃ $\frac{u^{2}}{g}$ = 3 km

AT q = 45⁰, R¢ = $\frac{u^{2}\sin 90º}{g}$ = $\frac { u ^ { 2 } } { g }$ = 3 km