Question

The range of a projectile for a given initial velocity is maximum when the angle of projection is $45^{o}$. The range will be minimum, if the angle of projection is

• A. $90^{o}$
• B. $180^{o}$
• C. $60^{o}$
• D. $75^{o}$

Answer 1

Answer: (A)

$90^{o}$

Answer 2

Range$= \frac{u^{2}\sin 2\theta}{g}$; when $\theta = 90{^\circ}$, $R = 0$ i.e. the body will fall at the point of projection after completing one dimensional motion under gravity.