Question

The range of a particle when launched at an angle of $15^{o}$ with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of $45^{o}$ to the horizontal

• A. 1.5 km
• B. 3.0 km
• C. 6.0 km
• D. 0.75 km

Answer 1

Answer: (B)

3.0 km

Answer 2

$R_{15{^\circ}} = \frac{u^{2}\sin(2 \times 15{^\circ})}{g} = \frac{u^{2}}{2g} = 1.5km$

$R_{45{^\circ}} = \frac{u^{2}\sin(2 \times 45{^\circ})}{g} = \frac{u^{2}}{g} = 1.5 \times 2 = 3km$