Question

The random variable X has a probability distribution P(X) of the following form, where k is some number.

$P(X=x) \begin{cases} k & \quad \text{if } x=0\\\ 2k & \quad \text{if } \text{ x=1}\\\ 3k & \quad \text{if } \text{ x=2} \\\ 0 & \quad \text{otherwise} \end{cases}$

Then P(x≤2) is:

• A. 0
• B. 1
• C. $\frac{1}{6}$
• D. $\frac{1}{2}$

Answer 1

Answer: (B)

1

Answer 2

The correct option is (B):1