Question

The radius of two metallic spheres $A$ and $B$ are $r_{1}$ and $r_{2}$ respectively$(r_{1} > r_{2})$. They are connected by a thin wire and the system is given a certain charge. The charge will be greater

• A. On the surface of the sphere $B$
• B. On the surface of the sphere $A$
• C. Equal on both
• D. Zero on both

Answer 1

Answer: (B)

On the surface of the sphere $A$

Answer 2

After connection of wire, potential becomes equal

∴ $\frac{Q_{1}}{r_{1}} = \frac{Q_{2}}{r_{2}}$ ⇒ $\frac{Q_{1}}{Q_{2}} = \frac{r_{1}}{r_{2}}$ when (;fn) r₁ > r₂,

then $Q_{1} > Q_{2}$