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Chemistry Question on Bohr’s Model for Hydrogen Atom

The radius of the second Bohr orbit for hydrogen atom is: (Planck's Const. h=6.6262×10−34 Jsh =6 . 6262 \times 10^{-34}\, Js; mass of electron =9.1091×10−31 Kg=9 . 1091 \times 10^{-31}\, Kg charge of electron e=1.60210×10−19Ce =1 .60210 \times 10^{-19} C; permittivity of vacuum (ϵ0)=8⋅854185×10−12 Kg−1 m−3A2)\left.\left(\epsilon_{0}\right)=8 \cdot 854185 \times 10^{-12}\, Kg ^{-1}\, m ^{-3} A ^{2}\right)

A

$0.529, ??

B

$2.12, ??

C

$1.65, ??

D

$4.76, ??

Answer

$2.12, ??

Explanation

Solution

r=a0n2Z=0.529×4r= a_{0} \frac{n^{2}}{Z}= 0.529\times4 $=2.12 ,??