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Question: The radius of the nucleus <sub>8</sub>O<sup>16</sup> is 3 × 10<sup>–15</sup> m. The density of this ...

The radius of the nucleus 8O16 is 3 × 10–15 m. The density of this nucleus will be –

A

2.35 × 10–17kg m–3

B

3.35 × 1017kg m–3

C

2.35 × 1017kgm–3

D

3.35 × 10–17kg m–3

Answer

2.35 × 1017kgm–3

Explanation

Solution

d = = 16amu43π×(3×10−15)3\frac { 16 \mathrm { amu } } { \frac { 4 } { 3 } \pi \times \left( 3 \times 10 ^ { - 15 } \right) ^ { 3 } }