Question

The radius of the larger circle lying in the first quadrant and touching the line 4x + 3y –12 = 0 and the coordinate axes, is-

• A. 5
• B. 6
• C. 7
• D. 8

Answer 1

Answer: (B)

6

Answer 2

Circle centre which touch both coordinate axis
is (r, r) , circle touch the line 4x + 3y + 2 = 0

then p = r

$\frac { | 4 r + 3 r - 12 | } { \sqrt { 9 + 16 } }$ = r

7r –12 = ±5r

r= 6 r = 1

larger circle radius is = 6