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Question: The radius of the Earth is 6370 km and the radius of mars is 3440 km. What is the acceleration due t...

The radius of the Earth is 6370 km and the radius of mars is 3440 km. What is the acceleration due to Gravity on Mars if the mass of Mars is 1.11.1 times the mass of Earth?

Explanation

Solution

In this solution, we will use the formula of gravitational acceleration on a planet. We will find the gravitational acceleration on the surface of Earth and Mass and take their ratio to determine the acceleration due to gravity on the surface of Mars.
Formula used: In this solution, we will use the following formulae:
Gravitational acceleration on any planet: g=GMR2g = \dfrac{{GM}}{{{R^2}}} where GG is the gravitational constant, MM is the mass of the planet, and RRis the radius of the planet.

Complete step by step answer:
We’ve been given that the radius of the Earth is 6370 km and the radius of mars is 3440 km and the mass of Mars is 1.11.1 times the mass of Earth.
Let us denote the mass and radius of Earth as MeandRe{M_e}\,{\text{and}}\,{{\text{R}}_e} and the mass and radius of Mars as MmandRm{M_m}\,{\text{and}}\,{{\text{R}}_m}.
Then the gravitational acceleration on the surface of Earth will be
ge=GMe(6370)2{g_e} = \dfrac{{G{M_e}}}{{{{\left( {6370} \right)}^2}}}
And the gravitational acceleration on the surface of Mars will be
gm=GMm(3440)2{g_m} = \dfrac{{G{M_m}}}{{{{\left( {3440} \right)}^2}}}
Taking the ratio of the two gravitational acceleration, we get
gegm=MeMm×(34406370)2\dfrac{{{g_e}}}{{{g_m}}} = \dfrac{{{M_e}}}{{{M_m}}} \times {\left( {\dfrac{{3440}}{{6370}}} \right)^2}
Now we’ve been given that the mass of Mars is 1.11.1 times the mass of Earth so we can write that mathematically as Mm=1.1Me{M_m} = 1.1{M_e}. So, the above equation will be transformed as
gegm=11.1×(34406370)2\dfrac{{{g_e}}}{{{g_m}}} = \dfrac{1}{{1.1}} \times {\left( {\dfrac{{3440}}{{6370}}} \right)^2}
Which gives us
gegm=0.265\dfrac{{{g_e}}}{{{g_m}}} = 0.265
Now we know that the gravitational acceleration on the surface of Earth is ge=9.81m/s2{g_e} = 9.81\,m/{s^2} so we can find the gravitational acceleration on the surface of Mars as
gm=9.810.265=37m/s2{g_m} = \dfrac{{9.81}}{{0.265}} = 37\,m/{s^2}

Note: The dimensions of Mars are different in reality than what is actually mentioned in the question. But this question tests the concepts of gravitational acceleration and its dependence on the mass and radius of a planet.