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Question

Physics Question on Ray optics and optical instruments

The radius of the convex surface of planoconvex lens is 20cm20\,cm and the refractive index of the material of the lens is 1.51.5. The focal length is:

A

30 cm

B

50 cm

C

20 cm

D

40 cm

Answer

40 cm

Explanation

Solution

Using the relation for focal length of Plano convex lens
1f=(μ1)(1R11R2)\frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)
(Refractive index of material of lens μ=1.5,R1=20cm,R2=)\mu=1.5,\left.R_{1}=20\, cm , R_{2}=\infty\right)
1f=(1.51)(1201)\frac{1}{f}=(1.5-1)\left(\frac{1}{20}-\frac{1}{\infty}\right)
1f=140\frac{1}{f}=\frac{1}{40}
or f=40cmf=40\, cm