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Question

Physics Question on Ray optics and optical instruments

The radius of the convex surface of plano-convex lens is 20cm20\, cm and the refractive index of the material of the lens is 1.5.1.5 . The focal length is :

A

30 cm

B

50 cm

C

20 cm

D

40 cm

Answer

40 cm

Explanation

Solution

Using the relation for focal length of plano-convex lens 1f=(μ1)(1R11R2)\frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right) (Refractive index of material of lens μ=1.5\mu=1.5 R1=20cm,R2=R_{1}=20\, cm , R_{2}=\infty) 1f=(1.51)(1201)\frac{1}{f}=(1.5-1)\left(\frac{1}{20}-\frac{1}{\infty}\right) 1f=140\frac{1}{f}=\frac{1}{40} or f=40cmf=40\, cm