Question

The radius of the circle $x^2+Y^2+4x+6y+13=0$ is

• A. $\sqrt{26}$
• B. $\sqrt{13}$
• C. $\sqrt{23}$
• D. $0$

Answer 1

Answer: (D)

$0$

Answer 2

Given equation is
$x^2 + y^2 + 4x + 6y + 13 = 0$
or $(x^2 + 4x + 4) + (y^2 + 6y + 9) + 13 = 4 + 9$
or $(x+2)^2(y+3)^2=0$
$\therefore$ Radius of circle $= 0$.