Question

The radius of the circle $x ^ { 2 } + y ^ { 2 } + 4 x + 6 y + 13 = 0$ is.

• A. $\sqrt { 26 }$
• B. $\sqrt { 13 }$
• C. $\sqrt { 23 }$
• D. 0

Answer 1

Answer: (D)

0

Answer 2

Given equation of circle is

$x ^ { 2 } + y ^ { 2 } + 4 x + 6 y + 13 = 0$

Radius = $\sqrt { g ^ { 2 } + f ^ { 2 } - c } = \sqrt { 4 + 9 - 13 } = 0$.