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Question: The radius of the circle passing through the point (6, 2) and two of whose diameters are x + y = 6 a...

The radius of the circle passing through the point (6, 2) and two of whose diameters are x + y = 6 and x + 2y = 4 is –

A

4

B

6

C

20

D

20\sqrt{20}

Answer

20\sqrt{20}

Explanation

Solution

Point of intersection of diameters is called centre of circle ̃ \ centre(8,–2), Circle passes through (6,2)

\r=(6–8)2+(2+2)2\sqrt{(6–8)^{2} + (2 + 2)^{2}}=20\sqrt{20}