Question

The radius of the circle passing through point (6, 2) and having x + y = 6 as its normal and

x + 2y = 4 as its diameter is

• A. 10
• B. $2\sqrt{5}$
• C. $5\sqrt{2}$
• D. $4\sqrt{5}$

Answer 1

Answer: (B)

$2\sqrt{5}$

Answer 2

Normal is diameter also

x + y = 6

x + 2y = 4

– – –

– y = 2

y = –2, x = 8

(8 , –2)

CP = $\sqrt{(8 - 6)^{2} + (2 + 2)^{2}}$

CP = $\sqrt{4 + 16}$

CP = 2$\sqrt{5}$