The radius of the (2^{\text {nd }}) orbit of (Li ^{2+}) is (... | Chemistry | SolveeIt | Solveeit

Today, August 18

Question

The radius of the $2^{\text {nd }}$ orbit of $Li ^{2+}$ is $x$ . The expected radius of the $3^{\text {rd }}$ orbit of $Be ^{3+}$ is

A

$\frac{16}{27} \pi$

B

$\frac{4}{9} x$

C

$\frac{9}{4} x$

D

$\frac{27}{16} x$

Answer

$\frac{27}{16} x$

Explanation

Solution

Li2+
r2=x=k×322=24k
Be3+
r3=y=k×432
xy=49×43=1627
y=1627x