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Question

Physics Question on Moment Of Inertia

The radius of gyration of a solid cylinder of mass MM and radius RR about its own axis is

A

R2\frac{R}{\sqrt{2}}

B

R2\frac{R}{2}

C

R3\frac{R}{\sqrt{3}}

D

R3\frac{R}{3}

Answer

R2\frac{R}{\sqrt{2}}

Explanation

Solution

The radius of gyration of a solid cylinder k=IM=MR22k=\sqrt{\frac{I}{M}}=\sqrt{\frac{M R^{2}}{2}} k=R2k=\frac{R}{\sqrt{2}}