Question

The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be_________m. Given the length of the rod is $10\sqrt3\; m$.

Answer 1

$I = \frac{ML^2}{12}$

= $MK^2$

$K = \frac{L}{ \sqrt{12}}$

= $\frac{10\sqrt{3}}{\sqrt{12}}$

= $5 \;m$