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Question

Physics Question on System of Particles & Rotational Motion

The radius of gyration of a body about an axis at a distance of 6cm6\, cm from its centre of mass is 10cm10\, cm. Then, its radius of gyration about a parallel axis through its centre of mass will be

A

800 cm

B

8 cm

C

0.8 cm

D

80 m

Answer

8 cm

Explanation

Solution

TAB=ICM+Mh2T_{A B}=I_{ CM }+M h^{2} MKAB2=MKCM2+Mh2M K_{AB}^{2}=M K_{ CM }^{2}+M h^{2} KAB2=KCM2+h2K_{A B}^{2}=K_{ CM }^{2}+h^{2} Given, KAB=10cm,h=6cmK_{A B}=10\, cm,\, h=6\, cm Putting them, we get KCM=8cmK_{ CM }=8\, cm