Question
Physics Question on Moment Of Inertia
The radius of gyration about an axis through the center of a hollow sphere with external radius a and internal radius b is
A
52(a5−b5)(a3−b3)
B
41(a2−b2)(a4−b4)
C
21(a3−b3)(a5−b5)
D
52(a3−b3)(a5−b5)
Answer
52(a3−b3)(a5−b5)
Explanation
Solution
Moment of inertia of a hollow sphere with external radius a and internal radius b is,
I=52M(a3−b3a5−b5)
Radius of gyration,
K=MI
⇒K=M52M(a3−b3a5−b5)
⇒K=52(a3−b3a5−b5)
So, the correct option is (D): 52(a3−b3a5−b5)