The radius of convergence of the power series \[\sum\_{n=1}^... | Real Analysis | SolveeIt | Solveeit

Today, August 24

Question

The radius of convergence of the power series $\sum_{n=1}^{\infty} \left(\frac{n^3}{4^n}\right) x^{5n}$ is

A

4

B

$\sqrt[5]{4}$

C

$\frac{1}{4}$

D

$\frac{1}{\sqrt[5]{4}}$

Answer

$\sqrt[5]{4}$

Explanation

Solution

The correct option is (B): $\sqrt[5]{4}$