Question

The radius of circle having its centre at (0, 3) and passing through the foci of the ellipse $\frac{x^{2}}{16}$+$\frac{y^{2}}{9}$=1 is-

• A. 3
• B. 3.5
• C. 4
• D. $\sqrt{12}$

Answer 1

Answer: (C)

4

Answer 2

Foci of ellipse (±$\sqrt{7}$, 0)

Radius = $\sqrt{(0 - \sqrt{7})^{2} + (3 - 0)^{2}}$ = $\sqrt{7 + 9}$= 4