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Question

Chemistry Question on Structure of atom

The radius of an electron orbit in a hydrogen atom is of the order of

A

10−8  m10^{-8}\,\,m

B

10−9  m10^{-9}\,\,m

C

10−11  m10^{-11}\,\,m

D

10−10 m10^{-10}\,m

Answer

10−10 m10^{-10}\,m

Explanation

Solution

Radius of nthn^{t h} orbit rn=0.53n2Z �r_{n}=0.53 \frac{n^{2}}{Z} \,� Here n=1n=1 and for hydrogen atom z=1z = 1 ∴r1=0.53(1)21 �\therefore r_{1}=0.53 \frac{(1)^{2}}{1} \,� =0.53×10−10m=53 pm=0.53 \times 10^{-10} m=53\, p m