Question

The radius of a sphere is (5.3 ± 0.1) cm. The percentage error in its volume is

• A. (a) $\frac { 0.1 } { 5.3 } \times 100$
• A. (b) $3 \times \frac { 0.1 } { 5.3 } \times 100$
• A. (c) $\frac { 0.1 \times 100 } { 3.53 }$
• A. (d) $3 + \frac { 0.1 } { 5.3 } \times 100$

Answer 1

(b)

Sol. $\because V = \frac { 4 } { 3 } \pi r ^ { 3 }$

∴ % error in volume

$= 3 \times \%$ error in radius.

$= \frac { 3 \times 0.1 } { 5.3 } \times 100$