Question

The radius of a soap bubble whose potential is 16V is doubled. The new potential of the bubble will be

• A. 2V
• B. 4V
• C. 8V
• D. 16V

Answer 1

Answer: (C)

8V

Answer 2

Potential $V \propto \frac{1}{r} \Rightarrow V' = \frac{V}{2} = 8V$