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Question

Physics Question on Surface tension

The radius of a soap bubble is rr and the surface tension of soap solution is TT. Keeping the temperature constant, the extra energy needed to double the radius of the soap bubble by blowing, is

A

16πr2T16\, \pi r^{2} T

B

32πr2T32\, \pi r^{2} T

C

8πr2T8\, \pi r^{2} T

D

24πr2T24\, \pi r^{2} T

Answer

24πr2T24\, \pi r^{2} T

Explanation

Solution

Given: Initial radius of soap bubble =r=r; Surface tension of soap solution =T=T and final radius of soap bubble =2r=2 r. We know that energy to blow the soap bubble of radius r,(E1)=2×4πr2×T=8πr2Tr,\left(E_{1}\right)=2 \times 4 \pi r^{2} \times T=8 \pi r^{2} T and energy to blow a soap bubble of radius 2r,(E2)=2 r,\left(E_{2}\right)= 2×4π(2r)2T=32πr2T.2 \times 4 \pi(2 r)^{2} T=32 \pi r^{2} T . Therefore extra energy needed =E2E1=32πr2T8πr2T=24πr2T=E_{2}-E_{1}=32 \pi r^{2} T-8 \pi r^{2} T=24 \pi r^{2} T