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Question: The radius of a planet is R<sub>1</sub> and a satellite revolves around it in a radius R<sub>2</sub>...

The radius of a planet is R1 and a satellite revolves around it in a radius R2s Time period of revolution is T. Find the acceleration due to gravity.

A

4π2R23R12T2\frac{4\pi^{2}R_{2}^{3}}{R_{1}^{2}T^{2}}

B

4π2R22R1T2\frac{4\pi^{2}R_{2}^{2}}{R_{1}T^{2}}

C

2π2R23R1T2\frac{2\pi^{2}R_{2}^{3}}{R_{1}T^{2}}

D

4π2R2T2\frac{4\pi^{2}R_{2}}{T^{2}}

Answer

4π2R23R12T2\frac{4\pi^{2}R_{2}^{3}}{R_{1}^{2}T^{2}}

Explanation

Solution

T = 2πR23/2GMorGM=4π2R23T2\frac{2\pi R_{2}^{3/2}}{\sqrt{GM}}orGM = \frac{4\pi^{2}R_{2}^{3}}{T^{2}}

and g = GMR12=4π2R23R12T2\frac{GM}{R_{1}^{2}} = \frac{4\pi^{2}R_{2}^{3}}{R_{1}^{2}T^{2}}