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Question

Mathematics Question on Applications of Derivatives

The radius of a circle is increasing at the rate of 0.7cm/s.0.7 cm/s. What is the rate of increase of its circumference?

Answer

The correct answer is 1.4cm/s.1.4cm/s.
The circumference of a circle (C)(C) with radius (r)(r) is given by C=2πrC = 2πr. Therefore, the rate of change of circumference (C)(C) with respect to time (t)(t) is given by,
dCdt=dCdt.drdt\frac{dC}{dt}=\frac{dC}{dt}.\frac{dr}{dt} (By chain rule)
=ddr(2πr)drdt=\frac{d}{dr}(2πr)\frac{dr}{dt}
π2.drdtπ^2.\frac{dr}{dt}
It is given that drdt=0.7cm/s\frac{dr}{dt}=0.7 cm/s
Hence, the rate of increase of the circumference is 2π(0.7)=1.4cm/s.2π(0.7)=1.4cm/s.