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Question

Question: The radioactivity of a certain radioactive element drops to 1/64 of its initial value in 30 seconds....

The radioactivity of a certain radioactive element drops to 1/64 of its initial value in 30 seconds. Its half life is.

A

2 seconds

B

4 seconds

C

5 seconds

D

6 seconds

Answer

5 seconds

Explanation

Solution

N=N0(12)t/TN064=N0(12)30/TT=306=5secN = N_{0}\left( \frac{1}{2} \right)^{t/T} \Rightarrow \frac{N_{0}}{64} = N_{0}\left( \frac{1}{2} \right)^{30/T} \Rightarrow T = \frac{30}{6} = 5\sec