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Question: The radioactive nucleus \(7N^{13}\)decays to \(6C^{13}\) through the emission of....

The radioactive nucleus 7N137N^{13}decays to 6C136C^{13} through the emission of.

A

Neutron

B

Proton

C

Electron

D

Positron

Answer

Positron

Explanation

Solution

7N13→6C13++1e07N^{13} \rightarrow_{6}C^{13} +_{+ 1}e^{0}