Question
Question: The radioactive atom \(_{{\text{84}}}^{{\text{210}}}{\text{Po}}\) decays by alpha emission. How woul...
The radioactive atom 84210Po decays by alpha emission. How would you write an equation showing the decay?
Solution
To answer this question what mass number and proton number is. What alpha particles are and how the mass number and proton number change when alpha particle emits. A radioactive decay equation shows the decaying radioactive nuclei and newly formed radioactive nuclei and the particles that emit.
Complete answer:
The atomic number is the number of protons present in the nucleus of an atom. Every atom has a unique atomic number.
The atomic representation is as follows:
ZAX
Xis the symbol of the atom.
Z is the atomic number of proton number.
Ais the atomic mass.
The helium nucleus is known as alpha particles. The representation of the helium nucleus is as follows:
24He
So, when an alpha particle emits from a radioactive nucleus. The atomic number of that nucleus decreases by two and the mass number of that nucleus decreases by four.
The equation for the emission of an alpha particle form polonium is shown as follows:
84210Po→82206Pb+24He
We know that lead has an atomic number 82 .
So, by the emission of alpha particle from 84210Po, the 82206Pb forms.
Therefore, the equation showing the decay of 84210Po is, 84210Po→82206Pb+24He
Note: The alpha particles are represented by 24α. The radioactive decay follows the law of conservation of mass. The atomic number is the number of the proton. The mass number is the sum of the number of protons and the number of neutrons. During the radioactive decay, the heavy radioactive element breaks into smaller radioactive nuclei elements and emits alpha, beta particles, electrons or gamma radiation.