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Question: The radio transmitter operates on a wavelength of 1500 m at a power of 400 kilowatt. The energy of r...

The radio transmitter operates on a wavelength of 1500 m at a power of 400 kilowatt. The energy of radio-photon in joule is

A

1.32 × 10–24 J

B

1.32 × 10–28 J

C

1.32 × 10–26 J

D

1.32 × 10–32 J

Answer

1.32 × 10–28 J

Explanation

Solution

E = hcλ\frac{hc}{\lambda}=6.63×10–34×3×1081500\frac{6.63 \times 10^{–34} \times 3 \times 10^{8}}{1500}J

= 6.635\frac{6.63}{5}× 10–28J = 1.3× 10–28Js