Solveeit Logo
Login

Question

Chemistry Question on States of matter

The r.m.s. velocity of molecules of a gas of density 4 kg m−34 \,kg \,m^{-3} and pressure 1.2×105Nm−21.2 \times10^{5} Nm^{-2} is

A

120 ms−1120 \,ms^{-1}

B

600 ms−1600 \,ms^{-1}

C

300 ms−1300 \,ms^{-1}

D

900 ms−1900 \,ms^{-1}

Answer

300 ms−1300 \,ms^{-1}

Explanation

Solution

vrms=3pdv_{ rms } =\sqrt{\frac{3 p}{d}} =3×1.2×1054=300 ms−1=\sqrt{\frac{3 \times 1.2 \times 10^{5}}{4}}=300\, ms ^{-1}