Question
Question: The r.m.s velocity of CO gas molecules at \(27{}^\circ C\) is approximately 1000 m/s. For \({{N}_{2}...
The r.m.s velocity of CO gas molecules at 27∘C is approximately 1000 m/s. For N2 molecules at 600 K, the r.m.s velocity is approximately:
(A)- 2000 m/s
(B)- 1414 m/s
(C)- 1000 m/s
(D)- 1500 m/s
Solution
The atoms or molecules move at different speeds and in random directions. The root mean square (r.m.s) velocity is the average velocity of all the gas particles, and this can be calculated using the formula-
μrms=m3RT
where μrmsis the root mean square velocity in m/sec
R is the ideal gas constant = 8.3145 (kg.m2/sec2)/K.mol
T is the absolute temperature in Kelvin
m is the mass of a mole of the gas in kilograms
Complete answer:
-In the relation between the temperature and the kinetic energy, we can relate temperature to the velocity of gas molecules.
Ek=23RT...(i)
We know that, Ek=21mv2...(ii)
-Equating (i) and (ii), for the value of velocity, we will get
v2=m3RT
-The root mean square velocity or vrmsis the square root of the average square velocity, i.e.
vrms=m3RT
-Here, according to the question,
vrmsfor CO = 1000 m/s
Molar mass of CO = 12 + 16 = 28 g/mol =2.8×10−2kg/mol
Molar mass of N2 = 14×14=28 g/mol =2.8×10−2kg/mol
(T)CO = 27 + 273 = 300 K
(T)N2 = 600 K
-Plugging in the values in the equation,
μrms,COμrms,N2=(T)COMN2(T)N2MCO
⇒1000μrms,N2=300×2.8×10−2600×2.8×10−2
Hence, μrms,N2=1414m/s
So, the correct answer is option B.
Note:
The root-mean-square speed gives the root mean square speed, not velocity. This is because velocity is a vector quantity, and hence it has magnitude as well as direction. The root-mean-square speed gives only the magnitude or speed. The temperature must be converted to Kelvin and the molar mass must be converted to kg/mol unit.