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Question: The quantity of heat required to raise one mole through one degree Kelvin for a monoatomic gas at co...

The quantity of heat required to raise one mole through one degree Kelvin for a monoatomic gas at constant volume is

A

32R\frac{3}{2}R

B

52R\frac{5}{2}R

C

72R\frac{7}{2}R

D

4R4R

Answer

32R\frac{3}{2}R

Explanation

Solution

(ΔQ)V=μCVΔT(\Delta Q)_{V} = \mu C_{V}\Delta TŽ (ΔQ)V=1×CV×1=CV(\Delta Q)_{V} = 1 \times C_{V} \times 1 = C_{V}

For monoatomic gas

CV=32RC_{V} = \frac{3}{2}R Ž (ΔQ)V=32R(\Delta Q)_{V} = \frac{3}{2}R