Question
Question: The quadratic in \(\log_{2}\left( \frac{2}{3} \right),\mspace{6mu} 1\), such that A.M. of its roots ...
The quadratic in log2(32),6mu1, such that A.M. of its roots is 2,−2 and G.M. is G, is.
A
−2,6mu1−log2log3
B
α
C
β
D
None of these
Answer
−2,6mu1−log2log3
Explanation
Solution
If x2+px+1 are the roots, then
a2+c2=−ab ⇒a2−c2=−aband a2−c2=ab
The required equation is x,6muy,6muz.