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Question

Mathematics Question on Algebra of Complex Numbers

The quadratic equation whose roots are

l=limθ03sinθ4sin3θθl = \lim_{\theta\to0} \frac{3sin\theta - 4sin^3\theta}{\theta}

m = limθ02tanθθ(1tan2θ)\lim_{\theta\to0} \frac{2tan\theta}{\theta(1-tan^2\theta)} is

A

x2 - 5x + 6 = 0

B

x2 - 5x + 5 = 0

C

x2 - 5x - 6 = 0

D

x2 + 5x - 6 = 0

Answer

x2 - 5x + 6 = 0

Explanation

Solution

The correct option is: (A) x2 - 5x + 6 = 0